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Questions  

If x[1,1] then sin12x1+x2 equals

a
2 tan−1⁡x
b
π - 2 tan−1⁡x
c
-π - 2 tan−1⁡x
d
none of these

detailed solution

Correct option is A

Let tan−1⁡x=θ. Then x=tan⁡θ. Now, −1≤x≤1⇒−1≤tan⁡θ≤1⇒−π4≤θ≤π4⇒−π2≤2θ≤π2∴ sin−1⁡2x1+x2=sin−1⁡(sin⁡2θ)        =2θ ∵−π4≤θ≤π4⇒−π2≤2θ≤π2     = 2tan−1⁡x

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