If $$-1$$≤x≤$$-12$$, then $$sin$$$$-13x-4x3$$ equals

Question

If $$-1$$≤x≤$$-12$$, then $$sin$$$$-13x-4x3$$ equals

Infinity Learn · Accepted Answer

−$$1$$≤x≤−$$12Let$$ $$x=$$$$sin$$θ.   Then  $$sin$$$$-13x-4x3=$$$$sin$$$$-13sin$$θ$$-4sin3$$θ                                                           $$=$$$$sin$$$$-1(sin3$$θ$$)$$  $$=$$$$sin$$$$-1($$$$sin$$$$(-($$π$$+3$$θ$$)))$$                                                            $$=$$−π−$$3$$θ                   $$=$$−π−$$3sin$$−$$1x$$                       $$x=$$$$sin$$θ⇒   −$$1$$≤$$sin$$θ≤−$$12$$⇒−π$$2$$≤θ≤−π$$6$$      ⇒−$$3$$$$π$$$$2$$≤$$3$$θ≤−π$$2$$⇒−π$$2$$≤π$$+3$$θ≤π$$2$$​     ⇒−π$$2$$≤−π$$+3$$θ≤π$$2$$

$If - 1 \leq x \leq - \frac{1}{2}, then \sin^{- 1} (3 x - 4 x^{3}) equals$

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If -1≤x≤-12, then sin-13x-4x3 equals

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$If - 1 \leq x \leq - \frac{1}{2}, then \sin^{- 1} (3 x - 4 x^{3}) equals$