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If $x \geq 1,$ then $2 \tan^{- 1} x + \sin^{- 1} (\frac{2 x}{1 + x^{2}})$ is equal to

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4tan−1⁡x

π/2

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Correct option is D

We have, sin−1⁡2x1+x2=π−2tan−1⁡x for x≥1 ∴ 2tan−1⁡x+sin−1⁡2x1+x2=2lan−1⁡x+π−2tan−1⁡x=π

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If x≥1, then 2tan−1⁡x+sin−1⁡2x1+x2 is equal to

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If $x \geq 1,$ then $2 \tan^{- 1} x + \sin^{- 1} (\frac{2 x}{1 + x^{2}})$ is equal to