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$If [\begin{array}{cc} 1 / 25 & 0 \\ x & 1 / 25 \end{array}] = {[\begin{array}{cc} 5 & 0 \\ - a & 5 \end{array}]}^{- 2}, then the value of x is$

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a/125

2a/125

2a/25

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Correct option is B

Let A=50−a5⇒adj⁡(A)=50a5⇒A−1=1|A|50a5 =12550a5⇒A−2=A−12 =12550a512550a5=162525010a25=12502a125125 Now, 1/250x1/25=12502a125125⇒x=2a/125

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If 1/250x1/25=50−a5−2, then the value of x is

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$If [\begin{array}{cc} 1 / 25 & 0 \\ x & 1 / 25 \end{array}] = {[\begin{array}{cc} 5 & 0 \\ - a & 5 \end{array}]}^{- 2}, then the value of x is$