If $\mathrm{x}=2+2^{2/3}+2^{1/3}$ then the value of x³ - 6x² +6x is

$$\begin{gathered} \mathrm{x}=2+2^{2/3}+2^{1/3} \\ x-2=2^{\frac{2}{3}}+2^{\frac{1}{3}} \\ cubing on both side \\ {\left(x-2\right)}^3={\left(2^{\frac{2}{3}}+2^{\frac{1}{3}}\right)}^3 \\ {x}^3-6x^2+12x-8=4+2+3.2(x-2) \\ {x}^3-6x^2+12x-8=6+6x-12 \\ {x}^3-6x^2+6x=2 \end{gathered}$$