If $$x=$$[$$729+6(2)(243)+15(4)(81)+20(8)(27)+15(16)(9)+6(32)3+64$$] [$$1+4(4)+$$ $$6(16)+$$ $$4(64)+256$$] then $$x-1x$$ is equal to

If $$x=$$[$$729+6(2)(243)+15(4)(81)+20(8)(27)+15(16)(9)+6(32)3+64$$] [$$1+4(4)+$$ $$6(16)+$$ $$4(64)+256$$] $$=1+361+24$$ $$=4634$$ $$=52$$ ∴$$x=5$$ Therefore, $$x-1x=5-15=245=4.8$$

Binomial theorem for positive integral Index

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$If x = \frac{[729 + 6 (2) (243) + 15 (4) (81) + 20 (8) (27) + 15 (16) (9) + 6 (32) 3 + 64]}{[1 + 4 (4) + 6 (16) + 4 (64) + 256]} then \sqrt{x} - \frac{1}{\sqrt{x}} is equal to$

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$If x = \frac{[729 + 6 (2) (243) + 15 (4) (81) + 20 (8) (27) + 15 (16) (9) + 6 (32) 3 + 64]}{[1 + 4 (4) + 6 (16) + 4 (64) + 256]} = \frac{{(1 + 3)}^{6}}{{(1 + 2)}^{4}} = \frac{4^{6}}{3^{4}} = 5^{2}$

$∴ \sqrt{x} = 5$
$Therefore, \sqrt{x} - \frac{1}{\sqrt{x}} = 5 - \frac{1}{5} = \frac{24}{5} = 4.8$

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Binomial theorem for positive integral Index

Remember concepts with our Masterclasses.

If x=[729+6(2)(243)+15(4)(81)+20(8)(27)+15(16)(9)+6(32)3+64] [1+4(4)+ 6(16)+ 4(64)+256] then x-1x is equal to

If x=[729+6(2)(243)+15(4)(81)+20(8)(27)+15(16)(9)+6(32)3+64] [1+4(4)+ 6(16)+ 4(64)+256] =1+361+24 =4634 =52 ∴x=5 Therefore, x-1x=5-15=245=4.8

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$If x = \frac{[729 + 6 (2) (243) + 15 (4) (81) + 20 (8) (27) + 15 (16) (9) + 6 (32) 3 + 64]}{[1 + 4 (4) + 6 (16) + 4 (64) + 256]} then \sqrt{x} - \frac{1}{\sqrt{x}} is equal to$