$\text{ If }x=\frac{[729+6(2\left)\right(243)+15(4\left)\right(81)+20(8\left)\right(27)+15(16\left)\right(9)+6(32)3+64] }{[1+4(4)+ 6(16)+ 4(64)+256]}\text{ then }\sqrt{x}-\frac{1}{\sqrt{x}}\text{ is equal to }$

$$\begin{gathered} \text{ If }x=\frac{[729+6(2\left)\right(243)+15(4\left)\right(81)+20(8\left)\right(27)+15(16\left)\right(9)+6(32)3+64] }{[1+4(4)+ 6(16)+ 4(64)+256]} \\ =\frac{{\left(1+3\right)}^6}{{\left(1+2\right)}^4} \\ =\frac{4^6}{3^4} \\ =5^2 \end{gathered}$$

 

$\therefore \sqrt{x}=5$

$\text{ Therefore, }\sqrt{x}-\frac{1}{\sqrt{x}}=5-\frac{1}{5}=\frac{24}{5}=4.8$