If X is a variate taking values x1,x2,…,xn.Y is another variate taking values y1,y2,…,yn such that yi=2xi+3 and σY=8, then the variance of variable Z taking values 32xi;i=1, 2,…,n, is
24
36
6
18
We have,
yi=2xi+3;i=1,2,…n∴ Var(Y)=4Var(X)⇒ 64=4Var(X)⇒Var(X)=16
Now,
zi=32xi;i=1,2,…,n⇒ Var(Z)=94Var(X)=94×16=36