First slide
Geometric progression
Question

 If x=1+a+a2+., where |a|<1 and y=1+b+b2+ where b<1, then 1+ab+1+ab+a2b2+=

Moderate
Solution

x=11a and y=11ba=x-1x and b=y-1y 1+ab+a2b2+.....=11-ab=xyx+y-1

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