If x=1+a+a2+….∞, where |a|<1 and y=1+b+b2+…∞ where b<1, then 1+ab+1+ab+a2b2+…∞=
xyx+y−1
x+y−1yx
xyx+y+1
x+y+1xy
x=11−a and y=11−b⇒a=x-1x and b=y-1y ∴1+ab+a2b2+.....∞=11-ab=xyx+y-1