If A=x:−25≤x≤π−25, B=y:−1≤y≤1 and f(x)=cos(5x+2) then the mapping f:A→B is
One-one but not onto
Onto but not one - one
Both one - one and onto
Neither one - one nor onto
Let t=5x+2, then A=t:0≤1≤π
∴f(t)=cost which is bijective in 0,π
Hence f(x) is bijective