If a, x1, x2 are in G.P. with common ratio r, and b, y1, y2 are in G.P. with common ratio s where s – r = 2, then the area of the triangle with vertices (a, b), (x1, y1) and (x2, y2) is
ab(r2-1)
ab(r2-s2)
ab(s2-1)
abrs
Area of the triangle
=12 ab1arbs1ar2bs21=12ab(r−1)(s−1)(s−r)∣ =|ab(r−1)(r+1)|=abr2−1