If x1 and x2 are two distinct roots of the equation acosx+bsinx=c, then tanx1+x22 is equal to
ab
ba
ca
ac
acosx+bsinx=c⇒ a1−tan2x21+tan2x2+2btanx21+tan2x2=c⇒ (c+a)tan2x2−2btanx2+c−a=0⇒ tanx12+tanx22=2bc+a and tanx12tanx22=c−ac+a⇒ tanx1+x22=2bc+a1−c−ac+a=2b2a=ba