If x2-3x+2 be factor of x4-px2+q, then (p,q)=

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[3, 4]

[4, 5]

[4, 3]

[5, 4]

answer is D.

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Detailed Solution

x2-3x+2 be factor of x4-px2+q=0Hence (x2-3x+2)=0⇒(x-2)(x-1)=0⇒x=2, 1, putting these values in given equationso 4p-q-16=0 ....(i)and p-q-1=0 ..(ii)Solving (i) and (ii), we get [p,q]=[5,4]

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