First slide
Theory of equations
Question

If x2+x+1  is a factor of ax3+bx2+cx+d then the real root of ax3+bx2+cx+d=0 is, 

Moderate
Solution

 It is given that x2+x+1 is a factor of ax3+bx2+cx+d 

But  x2+x+1=0  has its roots as ω  and  ω2  . So, two imaginary roots of

ax3+bx2+cx+d=0  are ω  and   ω2Let the third real root be  α

Then, 

   ωω2α=(1)3daα=da

Hence, the real root of   ax3+bx2+cx+d=0  is  da.

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