If x2+x+1 is a factor of ax3+bx2+cx+d then the real root of ax3+bx2+cx+d=0 is,
da
−da
−ba
ba
It is given that x2+x+1 is a factor of ax3+bx2+cx+d
But x2+x+1=0 has its roots as ω and ω2. . So, two imaginary roots of
ax3+bx2+cx+d=0 are ω and ω2. Let the third real root be α
Then,
ωω2α=(−1)3da⇒α=−da
Hence, the real root of ax3+bx2+cx+d=0 is −da.