If x2+x+1 is a factor of ax3+bx2+cx+d then the real root of ax3+bx2+cx+d=0 is,
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a
da
b
−da
c
−ba
d
ba
answer is B.
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Detailed Solution
It is given that x2+x+1 is a factor of ax3+bx2+cx+d But x2+x+1=0 has its roots as ω and ω2. . So, two imaginary roots ofax3+bx2+cx+d=0 are ω and ω2. Let the third real root be αThen, ωω2α=(−1)3da⇒α=−daHence, the real root of ax3+bx2+cx+d=0 is −da.