If x2−3x+2 is a factor of x4−ax2+b=0 then the equation whose roots are a and b is
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a
x2+9x+20=0
b
x2−9x−20=0
c
x2−9x+20=0
d
x2+9x−20=0
answer is C.
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Detailed Solution
x4−ax2+b=x2−3x+2p(x) =(x−1)(x−2)p(x)where p(x) is a polynomial of degree 2∴1−a+b=0 and 16−4a+b=0⇒a=5,b=4Thus, equation whose roots are a and b isx2−9x+20=0