if A={x:x∈I,−2≤x≤2},B={x∈I,0≤x≤3},C={x:x∈N,1≤x≤2} and D={x,y)∈N×N;x+y=8} Then.
n(A∪(B∪C)=5
n(D) = 6
n(B∪C)=5
none of these
A = {– 2, – 1, 0, 1, 2}, B = {0, 1, 2, 3}, C = {1, 2}
so B∪C={0,1,2,3}
A∪(B∪C)={−2,−1,0,1,2,3}
so n(A∪(B∪C)=6,n(B∪C)=4
and D = {(1, 7), (2, 6), (3, 5), (4, 4), (5,3), (6, 2), (7, 1)}
so n(D) = 7.