Q.
If x2-x+1=0 then ∑r=12011xr+1xr3
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a
0
b
1
c
-1
d
4
answer is B.
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Detailed Solution
x2−x+1=0⇒x=−w,−w2S=t1+t2+t3+......t2011t1=1t2=-1; t3=-8t4=-1t5=1t6=8∴S=0+t2011=1
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