If |x-2|+|x-3|=7, then x=
6
-1
6 or -1
None of these
Here x = 2 and 3 are the critical points.
when x<2, |x-2|=-(x-2), |x-3|=-(x-3)
∴ x=-1 is a solution.
When 2≤x<3, |x-2|=x-2, |x-3|=-(x-3)
∴The equation reduces to x-2+3-x=7⇒1=7
∴ No solution in this case.
When x≥3, the equation reduces to
x-2+x-3=7⇒x=6>3
Hence we get, x=6 or -1