if∫$$3x+1$$−$$7x$$−$$121xdx=K13$$−$$x+K27$$−$$x+C$$ then

Correct option is 3K1=17log⁡3,K2=−3log⁡7

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if $\int \frac{3^{x + 1} - 7^{x - 1}}{21^{x}} d x = K_{1} 3^{- x} + K_{2} 7^{- x} + C$ then

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K1=17log⁡3,K2=13log⁡7

K1=17log⁡3,K2=−13log⁡7

K1=17log⁡3,K2=−3log⁡7

k1=3log⁡7,k2=−7log⁡3

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detailed solution

Correct option is C

∫3x+1−7x−121xdx=3∫7−xdx−17∫3−xdx=−37−xlog⁡7+173−xlog⁡3+CK1=17log⁡3,K2=−3log⁡7

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if∫3x+1−7x−121xdx=K13−x+K27−x+C then

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if $\int \frac{3^{x + 1} - 7^{x - 1}}{21^{x}} d x = K_{1} 3^{- x} + K_{2} 7^{- x} + C$ then