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Q.

If ∫2x+1−5x−110xdx ==A15xlog⁡15+B12xlog⁡12+c then

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a

A=25, B=15

b

A=25, B=-15

c

A=2, B=-15

d

A=2, B=15

answer is C.

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Detailed Solution

I=∫2x+1−5x−110xdx=∫5x 2x25x−15· 2x10xdx=∫215x−1512xdx=215xlog⁡15−1512xlog⁡12+c   formula ∫axdx=axloge⁡a+c
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If ∫2x+1−5x−110xdx ==A15xlog⁡15+B12xlog⁡12+c then