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 If 1x7x1+x7dx=aln|x|+blnx7+1+c, then 

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a
a=1, b=27
b
a=-1, b=27
c
a=1, b=-27
d
a=-1, b=-27

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detailed solution

Correct option is C

I=∫1−x7x1+x7dx=aln⁡|x|+bln⁡1+x7+C Differentiating both sides, we get 1−x7x1+x7=ax+b⋅7x61+x7⇒ 1−x7=a1+x7+7bx7⇒ a=1,a+7b=−1⇒ b=−27


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