First slide
Introduction to integration
Question

If x+1x2+x+1dxx2+x+1=kx1x2+x+1+C then the value of k

Easy
Solution

Differentiating both the sides w.r.t.x, and simplifying , we get 

x+1x2+x+13/2=3k2x+1x2+x+13/2k=23

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