If ∫2x+57-6x-x2dx=A7-6x-x2+Bsin-1x+34+C (where C is a constant of integration), then the ordered pair (A,B) is equal to:
−2,−1
2, 1
−2, 1
2,−1
Let I=∫2x+57-6x-x2dx
=∫2x+6−17−6x−x2dx
=−∫−2x−67−6x−x2dx−∫116−x+32dx
∴I=−27−6x−x2−sin−1x+34
=A7−6x−x2+Bsin−1x+34
⇒A=−2,B=−1