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 If 2x+57-6x-x2dx=A7-6x-x2+Bsin-1x+34+C (where C is a constant of integration), then the ordered pair (A,B) is equal to: 

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a
−2,−1
b
2, 1
c
−2, 1
d
2,−1

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detailed solution

Correct option is A

Let I=∫2x+57-6x-x2dx=∫2x+6−17−6x−x2dx=−∫−2x−67−6x−x2dx−∫116−x+32dx ∴I=−27−6x−x2−sin−1x+34=A7−6x−x2+Bsin−1x+34⇒A=−2,B=−1


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