If x3+3x2−9x+λ is of the form (x−α)2(x−β), then λ is equal to

Since, f(x)=x3+3x2−9x+λ=(x−α)2(x−β)∴α is a double root.∴f′(x)=0 has also one root α.i.e. 3x2+6x−9=0 has one root α.∴ x2+2x−3=0 or (x+3)(x−1)=0has the root α which can either -3 or 1.If α=1, then f(1)=0 gives λ−5=0⇒λ=5If α=−3, then f(−3)=0 gives              −27+27+27+λ=0⇒     λ=−27