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If , then is any term of
the following
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a
3, 6, 9, 12,…
b
9, 18, 27, 36, …
c
6, 12, 18, 24,…
d
65, 125, 185...
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Correct option is C
Since x2, x3 ∈ I, so x2 + x3 ∈ IThus 5x6 ∈ I ⇒ x = 65n, n ∈ ISubstituting this value in x2 + x3 =5x6, we have35n+25n=n⇒35n−35n+25n−25n=n⇒35n+25n=0⇒35n=0=25n (Since 0≤{x}<1)Thus 3n = 5m1, 2n = 5m2 Therefore xn=2n.3n5=5m1×5m25=5m1m2⇒x⋅5m13=5m1m2⇒ x=3m2Similarly x.5m22 = 5m1m2 ⇒ x = 2m1Hence x is multiple of 2 and 3 so of 6 and x∈I
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