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If are three consecutive terms of an A.P., then the values of a are given by
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a
a≥12
b
a>12
c
a<12
d
a≤12
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Correct option is A
Since, 51+x+51−x,a2,25x+25−x are in A.P., we have 2a2=51+x+51−x+25x+25−xNow put 5x = t so that t > 0, we then havea=5t+5t+t2+1t2=t2+1t2+5t+1tor a=t−1t2+2+5t−1t2+2=t−1t2+5t−1t2+12≥12Thus, values of a are given by the inequality a ≥ 12.Similar Questions
If and 1 are in A.P, then x is equal to
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