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Q.

If 3x5−7x4+4x3+ax2+bx+c=0  is a reciprocal equation of second type then (a, b, c)=

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a

(3, -7, 4)

b

(-3, 7, -4)

c

(-4, 7, -3)

d

(4, -7, 3)

answer is C.

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Detailed Solution

3x5−7x4+4x3+ax2+bx+c=0  given that it is a reciprocal equation of second type hence 3=-c, -7=-b,4=-a  ⇒a,b,c=-4,7,-3
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If 3x5−7x4+4x3+ax2+bx+c=0  is a reciprocal equation of second type then (a, b, c)=