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$If (1 + x) (1 + x^{2}) (1 + x^{4}) \dots (1 + x^{128}) = \sum_{r = 0}^{n} x^{r} then n is$

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Correct option is A

(1+x)(1+x2)(1+x4)...(1+x128)=1+x+...+xn=1-xn+11-x sum of n'terms in G.P=a1-rn1-r →1−x256=1−xn+1→n+1=256=n=255

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If (1+x)1+x21+x4…1+x128=∑r=0n xr then n is

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$If (1 + x) (1 + x^{2}) (1 + x^{4}) \dots (1 + x^{128}) = \sum_{r = 0}^{n} x^{r} then n is$