If (7-43)x2-4x+3+(7+43)x2-4x+3=14 then the value of x is given by

We know that  7+437−43=1 , Therefore, the given equation becomes y+1y=14 where y=7−43x2−4x+3⇒y2−14y+1=0⇒y=7±43 Now y=7+43⇒x2−4x+3=−1⇒x=2,2Also y=7−43⇒x2−4x+3=1⇒x=2±2