If Δ(x)=x2+4x−32x+4132x2+5x−94x+5268x2−6x+116x−6104=ax3+bx2+cx+d, then
a=3
b=0
c=0
None of these
Δ′(x)=2x+42x+4134x+54x+52616x−616x−6104+x2+4x−32132x2+5x−94268x2−6x+116104=0+2×13×(0)=0⇒Δ(x)= constant ⇒a=0,b=0,c=0