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If x42x2x2xx42x2x2xx4=A+BxxA2then ordered pair A,B

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a
−4,−5
b
−4,3
c
−4,5
d
4,5

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detailed solution

Correct option is C

We have, x-42xx2xx-42x2x2xx-4                     R3→R3−R1+R3                 =5x−45x−45x−42xx−42x2x2xx−4             =(5X-4)1112xx-42x2x2xx-4 C2→C2-C1,C3→C3-C1  =(5X-4)1002x-4-x02x0-4-x               =(5x-4)(4+x)2∴A=-4  B=5


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