If Δ(x)=x2+4x−3 2x+4 132x2+5x−9 4x+5 268x2−6x+1 16x−6 104=ax3+bx2+cx+d, then
a = 3
b = 0
c = 0
None of these
Δ'(x)= 2x+42x+4134x+54x+52616x−616x−6104+x2+4x−32132x2+5x−94268x2−6x+116104 =0+2×13×(0)=0
⇒ Δ(x)= constant ⇒a=0, b=0, c=0