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If 1+x+x248=a0+a1x+a2x2++a96x96 then the value of  a0a2+a4a6++a96 

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By Expert Faculty of Sri Chaitanya
a
-1
b
0
c
1
d
48

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detailed solution

Correct option is C

Putting x = i, we get1+i+i248=a0+a1i+a2i2+…+a98i96⇒ i48=a0−a2+a4−…+ia1−a3+…Equating the real parts we geta0−a2+a4−a6+…+a96=1


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