If 1+x+x248=a0+a1x+a2x2+…+a96x96 then the value of  a0−a2+a4−a6+…+a96

Putting x = i, we get1+i+i248=a0+a1i+a2i2+…+a98i96⇒ i48=a0−a2+a4−…+ia1−a3+…Equating the real parts we geta0−a2+a4−a6+…+a96=1