If  x2+xx+1x−22x2+3x−13x3x−3x2+2x+32x−12x−1=Ax+B then A is equal to:

Applying R2→R2−R1−R3 we get,Ax+B=x2+xx+1x−2−400x2+2x+32x−12x−1Expanding along R2, we getAx+B=(−1)(−4)x+1x−22x−12x−1=43x−202x−1=4(3)(2x−1)=24x−12Thus A = 24