If x2+2x+2xy+my-3 has two rational factors, then the value of m will be

Given expression x2+2x+2xy+my-3 can be written as x2+2x(1+y)+(my-3)But factors are rational, so B2-4 AC is perfect square.Now 4{(1+y)2-(my-3)}≥0⇒4{y2+1+2y-m+3}≥0⇒y2+2y-my+4≥0Hence 2y-m=±4y {as it is perfect square}⇒2y-my=4y⇒m=-2.Now taking (-) sign, we get m=6.