If 2x2−5xy+2y2=0 represents two sides of a triangle whose centroid is (1, 1) then the equation of the third side is
x+y-3=0
x-y-3=0
x+y+3=0
x-y+3=0
a=2,2h=−5,b=2,(x1,y1)=(1,1)
Equation of third side is S1=32S11
axx1+h(xy1+x1y)+byy1
=32(ax12+2hx1y1+by12)
⇒x+y−3=0