If x2+4xy+y2=0 represents two sides of ΔOAB and the orthocentre is (-1, -1), then the third side is
x+y=2
x+y=1
x+y+1=0
x+y=3
a=1,2h=4,b=1(l,m)=(−1,−1)
(a+b)(lx+my)=am2−2hlm+bl2
⇒x+y=1