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If $x = 2 + \sqrt{3}, xy = 1, then \frac{x}{\sqrt{2} + \sqrt{x}} + \frac{y}{\sqrt{2} - \sqrt{y}} =$

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Correct option is A

y=1x=12+3=2-34-3=2-3 ∴x2+xy2-y=x2-x2-x+y(2+y)2-y ⇒xx-2x-2+yy+22-y-xx-23+yy+23 =13xx+yy+2y-x=132+33/2+2-33/2+2-23 =13123/24+233/2+123/24-233/2-26 =13122(3+1]3+3-13-26 =131222.33+63-26 =1336-26=2.

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If x=2+3, xy=1, then x2+x+y2-y=

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If $x = 2 + \sqrt{3}, xy = 1, then \frac{x}{\sqrt{2} + \sqrt{x}} + \frac{y}{\sqrt{2} - \sqrt{y}} =$