If x1,y1 are roots of x2+8x−20=0 ,x2,y2 are the roots of 4x2+32x−57=0 and (x3,y3) are the roots of 9x2+72x−112=0 , then the points (x1,y1) ,(x2,y2) and (x3,y3)
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a
Are collinear
b
Form an equilateral triangle
c
Form a right angled isosceles triangle
d
Are concyclic
answer is A.
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Detailed Solution
x1+y1=−8,x2+y2=−324=−8,x3+y3=−729=−8 ∴ the determinant =|1x1y11x2y21x3y3|=|1x1+y1y11x2+y2y21x3+y3y3|=|1−8y11−8y21−8y3|=0 [first and second columns are proportional]Hence, the points (x1,y1),(x2,y2) and (x3,y3) are collinear.