Equation of line in Straight lines

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If $3 x - 4 y + 5 = 0$ and $ax + 2 y + 4 = 0$ are parallel to each other then a=

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Solution

Two lines $a_{1} x + b_{1} y + c_{1} = 0$ and $a_{2} x + b_{2} y + c_{2} = 0$ are parallel if and only if $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}}$
It implies that $\frac{3}{a} = \frac{- 4}{2}$
Cross multiply and then simplify
$\begin{matrix} - 4 a = 6 \\ a = - \frac{3}{2} \end{matrix}$
Therefore, the value of a is $a = - 1.5$

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Equation of line in Straight lines

Remember concepts with our Masterclasses.

If 3x−4y+5=0 and ax+2y+4=0 are parallel to each other then a=

Two lines a1x+b1y+c1=0 and a2x+b2y+c2=0 are parallel if and only if a1a2=b1b2It implies that 3a=−42Cross multiply and then simplify −4a=6a=-32 Therefore, the value of a is a=-1.5

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If $3 x - 4 y + 5 = 0$ and $ax + 2 y + 4 = 0$ are parallel to each other then a=