If xa+yb=1 intersects 5x2+5y2+5bx+5ay−9ab=0 at P and Q, ∠POQ=π/2 then the relation between a and b is
a = b
a = 2b or b = 2a
a = 3b or b = 3a
a + b = 5
Homogenising,
5x2+5y2+(5bx+5ay)xa+yb−9abxa+yb2=0
coefficient of x2 + coefficient of y2
⇒5+5ba−9ba+5+5ab−9ab=0
⇒b(5a−4b)+a(5b−4a)=0
⇒(a−2b)(2a−b)=0