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If $\frac{x}{y} = \frac{\cos A}{\cos B}$ then $\frac{x \tan A + y \tan B}{x + y} =$

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sin⁡A+cos⁡Bcos⁡A+sin⁡B

sin⁡A+sin⁡Bcos⁡Acos⁡B

tan⁡A+B2

cot⁡A−B2

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detailed solution

Correct option is C

xcos⁡A=ycos⁡B so xtan⁡A+ytan⁡Bx+y =cos⁡Atan⁡A+cos⁡Btan⁡Bcos⁡A+cos⁡B=sin⁡A+sin⁡Bcos⁡A+cos⁡B=2sin⁡A+B2cos⁡A−B22cos⁡A+B2cos⁡A−B2=tan⁡A+B2

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If xy=cos⁡Acos⁡B then xtan⁡A+ytan⁡Bx+y=

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free study material

If $\frac{x}{y} = \frac{\cos A}{\cos B}$ then $\frac{x \tan A + y \tan B}{x + y} =$