Download the app

Questions  

If  x2ydxx3+y3dy=0y0=1  and  y3logy=kx3 then k = 

Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
a
12
b
13
c
1
d
2

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is B

⇒dydx=x2yx3+y3=y/x1+(y/x)3V+xdvdx=v1+v3( put y=vx)⇒xdvdx=−v41+v3∫1+v3v4dv=−∫dxx⇒∫v−4+1vdv=−∫1xdx⇒v−3−3+ln⁡v=−ln⁡x+c⇒ln⁡xyx−13v3=cln⁡y−x33y3=cy(0)=1⇒c=0    ∴log⁡y=x33y3


Similar Questions

 The solution of the differential equation 3xy13y+x2y21/2=0 satisfying the condition y(1)=1 is


whats app icon
phone icon