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If 3A=122212x2y and AA=I, then 3A=122212x2y and AA=I, then x+y is equal to 

a
-3
b
-2
c
-1
d
0

detailed solution

Correct option is A

(3A)′=12x2122−2yNow, 9I=(3A)(3A)′=12221−2x2y12x2122−2y=90x+4+2y092x+2−2yx+4+2y2x+2−2yx2+4+y2⇒x+2y+4=02x−2y+2=0x2+y2+4=9⇒x=−2, y=−1

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