Questions
If then
a
The number of values ofx∈ 0,4πare 4
b
The number of values of x∈[0,4π]are 2
c
The number of values of y∈[0,4π]are 4
d
The number of values of y∈0,4πare 8
detailed solution
Correct option is A
x+y=2π3⇒y=2π3−x∴sinx=2sin2π3−x = 232cosx+12sinx = 3cosx+sinx⇒cosx=0⇒x=nπ+π2⇒y=2π3−nπ−π2=π6−nπHence,x∈0,4π,x=π2,3π2,5π2,7π2and for x∈0,4π,y=π6,7π6,13π6,19π6Talk to our academic expert!
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