If x,y∈R and 2x2+6xy+5y2=1, then
|x|≤5
|x|≥5
y2≤2
y2≤4
2x2+6xy+5y2=1 (1)Equation (1) can be rewritten as2x2+(6y)x+5y2−1=0Since x is real, we have36y2−85y2−1≥0or y2≤2or −2≤y≤2Equation (1) can also be rewritten as 5y2+(6x)y+2x2−1=0Since y is real, we have 36x2−202x2−1≥0or 36x2−40x2+20≥0or −4x2≥−20or x2≤5or −5≤x≤5