First slide
Extreme values and Periodicity of Trigonometric functions
Question

If (x, y) satisfies the equation (x+5)2+(y12)2=196 then minimum value of x2+y2 is

Moderate
Solution

  Let  x+15=14cosθ, y-12=14sinθ 

(x+5)2+(y12)2=(14)2

Now         x=5+14cosθ

and          y=12+14sinθ

          x2+y2=365+28(12sinθ5cosθ)

      min=36528×13=1 

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