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If (x, y) satisfies the equation ${(x + 5)}^{2} + {(y - 12)}^{2} = 196$ then minimum value of $\sqrt{x^{2} + y^{2}}$ is

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Correct option is C

Let x+15=14cosθ, y-12=14sinθ ⇒(x+5)2+(y−12)2=(14)2Now x=−5+14cosθand y=12+14sinθ⇒ x2+y2=365+28(12sinθ−5cosθ)∴ min=365−28×13=1

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If (x, y) satisfies the equation (x+5)2+(y−12)2=196 then minimum value of x2+y2 is

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If (x, y) satisfies the equation ${(x + 5)}^{2} + {(y - 12)}^{2} = 196$ then minimum value of $\sqrt{x^{2} + y^{2}}$ is