If x,y∈0,2π and sinx+siny=2 then the value of x+y is
π
π2
3π
3π2
x∈[0,2π],y∈[0,2π] and sinx+siny=2
⇒sinx=1,siny=1
⇒x=π2,y=π2
⇒x+y=π2+π2=π