If 3x+y=0 is a tangent to the circle with centre at the point (2, -1), then the equation of the other tangent to the circle from the origin, is

It is given that 3x+y=0 is a tangent to the circle with centre at (2, -1). ∴ Radius = Length of the 1. from (2, -1) on 3 x + y = 0 ⇒ Radius =6−19+1=510=52So, the equation of the circle is (x−2)2+(y+1)2=52⇒x2+y2−4x+2y+52=0The combined equation of the tangents drawn from the origin to this circle isx2+y2−4x+2y+5252=−2x+y+522⇒3x2−8xy−3y2=0⇒3x+y=0,x−3y=0