If $$A=0$$ $$1$$ $$21$$ $$2$$ $$33$$ x $$1$$ and A−$$1=1/2$$−$$1/21/2$$−$$43y5/2$$−$$3/21/2$$, then

Correct option is 1x = 1, y = – 1

Questions

If $A = [\begin{array}{lll} 0 1 2 \\ 1 2 3 \\ 3 x 1 \end{array}]$ and $A^{- 1} = [\begin{array}{ccc} 1 / 2 & - 1 / 2 & 1 / 2 \\ - 4 & 3 & y \\ 5 / 2 & - 3 / 2 & 1 / 2 \end{array}]$ , then

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x = 1, y = – 1

x=−1,y=1

x = 2, y = – 1/2

x = 1/2, y = 1/2

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detailed solution

Correct option is A

We have 100010001=AA−1=0121233x11/2−1/21/2−43y5/2−3/21/2=10y+1012(y+1)4(1−x)3(x−1)2+xy⇒1−x=0,x−1=0,y+1=0,y+1=0,2+xy=1∴x=1,y=−1.

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If A=0 1 21 2 33 x 1 and A−1=1/2−1/21/2−43y5/2−3/21/2, then

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If $A = [\begin{array}{lll} 0 1 2 \\ 1 2 3 \\ 3 x 1 \end{array}]$ and $A^{- 1} = [\begin{array}{ccc} 1 / 2 & - 1 / 2 & 1 / 2 \\ - 4 & 3 & y \\ 5 / 2 & - 3 / 2 & 1 / 2 \end{array}]$ , then