If x−2y+4=0 and 2x+y−5=0 are the sides of a isosceles triangle having area 10 sq. units. Equation of third side is :
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a
x+3y=19
b
x−y−11=0
c
x−3y=19
d
3x−y+15=0
answer is A.
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Detailed Solution
Equation of third side can be 2x+y±(x−2y)=k and area of Δ=10sq ∴ Distance from (615,135) to third side is 10 ∴ Equation of third side is x+3y=19 or x+3y+1=0 or 3x−y+9=0 or 3x−y=11